What is expand (7x-3)/(4x(4x-7)) ?

The solution to expand (7x-3)/(4x(4x-7)) is (7x-3)/(16x^2-28x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (7x-3)/(4x(4x-7))

expand

\frac{7 x - 3}{4 x ( 4 x - 7 )}

\frac{7 x - 3}{16 x ^{2} - 28 x}

Solution steps

\frac{7 x - 3}{4 x ( 4 x - 7 )}

Expand

4 x (4 x - 7) : 16 x^{2} - 28 x

= \frac{7 x - 3}{16 x ^{2} - 28 x}

\frac{1 + k ( s + 11 )}{s ( s + 3 ) ( s + 5 )}

\frac{d}{d y} ((x (y)) (y^{2} + y))

[2 + 2] (2 + 1)^{k}

\frac{( x ^{2} + 3 x ) ^{2}}{2}

- \frac{6 ( s + 1 )}{( s ^{2} + 5 s + 6 )}

What is expand (7x-3)/(4x(4x-7)) ?
The solution to expand (7x-3)/(4x(4x-7)) is (7x-3)/(16x^2-28x)