What is expand ((x^2+3x)^2)/2 ?

The solution to expand ((x^2+3x)^2)/2 is (x^4)/2+3x^3+(9x^2)/2

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expand ((x^2+3x)^2)/2

expand

\frac{( x ^{2} + 3 x ) ^{2}}{2}

\frac{x ^{4}}{2} + 3 x^{3} + \frac{9 x ^{2}}{2}

Solution steps

\frac{( x ^{2} + 3 x ) ^{2}}{2}

(x^{2} + 3 x)^{2} = x^{4} + 6 x^{3} + 9 x^{2}

= \frac{x ^{4} + 6 x ^{3} + 9 x ^{2}}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{4} + 6 x ^{3} + 9 x ^{2}}{2} = \frac{x ^{4}}{2} + \frac{6 x ^{3}}{2} + \frac{9 x ^{2}}{2}

= \frac{x ^{4}}{2} + \frac{6 x ^{3}}{2} + \frac{9 x ^{2}}{2}

Divide the numbers:

\frac{6}{2} = 3

= \frac{x ^{4}}{2} + 3 x^{3} + \frac{9 x ^{2}}{2}

- \frac{6 ( s + 1 )}{( s ^{2} + 5 s + 6 )}

(2, - 2) y (5, - 3)

(- 2 x)^{\circ - 1} (x + y)

\frac{4}{( 3 - x ) ^{3}}

\frac{a + b ( a + b y )}{a - b ( a - b y )}

What is expand ((x^2+3x)^2)/2 ?
The solution to expand ((x^2+3x)^2)/2 is (x^4)/2+3x^3+(9x^2)/2