What is expand-3((-2,1,1)-(4,3,5)) ?

The solution to expand-3((-2,1,1)-(4,3,5)) is -3(-2*1*1,,)+3(4*3*5,,)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-3((-2,1,1)-(4,3,5))

expand

- 3 ((- 2, 1, 1) - (4, 3, 5))

- 3 (- 2 \cdot 1 \cdot 1,,) + 3 (4 \cdot 3 \cdot 5,,)

Solution steps

- 3 ((- 2, 1, 1) - (4, 3, 5))

= - 3 ((- 2 \cdot 1 \cdot 1,,) - (4 \cdot 3 \cdot 5,,))

Apply the distributive law:

a (b - c) = ab - a c

a = - 3, b = (- 2, 1, 1), c = (4, 3, 5)

= - 3 (- 2, 1, 1) - (- 3) (4, 3, 5)

Apply minus-plus rules

- (- a) = a

= - 3 (- 2 \cdot 1 \cdot 1,,) + 3 (4 \cdot 3 \cdot 5,,)

\frac{( 4 + x ) ^{3}}{8}

3 (e^{3 t} + C e^{- t}) + 8 e^{- t}

1 + (3 x^{2} - 6 x)^{2}

\frac{1}{( 2 + 5 x ) ^{3}}

\frac{( 2 x a + b ) ^{2}}{4 a ^{2}}

What is expand-3((-2,1,1)-(4,3,5)) ?
The solution to expand-3((-2,1,1)-(4,3,5)) is -3(-2*1*1,,)+3(4*3*5,,)