What is expand ((2xa+b)^2)/(4a^2) ?

The solution to expand ((2xa+b)^2)/(4a^2) is x^2+(bx)/a+(b^2)/(4a^2)

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expand ((2xa+b)^2)/(4a^2)

expand

\frac{( 2 x a + b ) ^{2}}{4 a ^{2}}

x^{2} + \frac{b x}{a} + \frac{b ^{2}}{4 a ^{2}}

Solution steps

\frac{( 2 x a + b ) ^{2}}{4 a ^{2}}

(2 x a + b)^{2} = 4 a^{2} x^{2} + 4 ab x + b^{2}

= \frac{4 a ^{2} x ^{2} + 4 ab x + b ^{2}}{4 a ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 a ^{2} x ^{2} + 4 ab x + b ^{2}}{4 a ^{2}} = \frac{4 a ^{2} x ^{2}}{4 a ^{2}} + \frac{4 ab x}{4 a ^{2}} + \frac{b ^{2}}{4 a ^{2}}

= \frac{4 a ^{2} x ^{2}}{4 a ^{2}} + \frac{4 ab x}{4 a ^{2}} + \frac{b ^{2}}{4 a ^{2}}

Cancel

\frac{4 a ^{2} x ^{2}}{4 a ^{2}} : x^{2}

= x^{2} + \frac{4 ab x}{4 a ^{2}} + \frac{b ^{2}}{4 a ^{2}}

Cancel

\frac{4 ab x}{4 a ^{2}} : \frac{b x}{a}

= x^{2} + \frac{b x}{a} + \frac{b ^{2}}{4 a ^{2}}

(4 - x) e - 2

\frac{3 ( x + 1 ) ( x - 4 )}{x ( 3 x - 13 )}

\frac{1}{( s + 3 ) ( s - 2 )}

x (y + y^{'} (x))

\frac{a + 7}{( a - 1 ) ( a - 2 ) ( a + 1 )}

What is expand ((2xa+b)^2)/(4a^2) ?
The solution to expand ((2xa+b)^2)/(4a^2) is x^2+(bx)/a+(b^2)/(4a^2)