What is expand (2x^2-4x+3)/((x-1)^2) ?

The solution to expand (2x^2-4x+3)/((x-1)^2) is (2x^2-4x+3)/(x^2-2x+1)

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expand (2x^2-4x+3)/((x-1)^2)

expand

\frac{2 x ^{2} - 4 x + 3}{( x - 1 ) ^{2}}

\frac{2 x ^{2} - 4 x + 3}{x ^{2} - 2 x + 1}

Solution steps

\frac{2 x ^{2} - 4 x + 3}{( x - 1 ) ^{2}}

(x - 1)^{2} = x^{2} - 2 x + 1

= \frac{2 x ^{2} - 4 x + 3}{x ^{2} - 2 x + 1}

((e^{8 x} - e^{- 8 x}))^{2}

in t er sec (a) (x - 1)^{2} - 4

\frac{z}{( z - a ) ( z - 1 )}

\frac{( - 8 X + A ) ^{2}}{16}

- \frac{2 ( 4 a ^{2} b ^{2} + 3 )}{b}

What is expand (2x^2-4x+3)/((x-1)^2) ?
The solution to expand (2x^2-4x+3)/((x-1)^2) is (2x^2-4x+3)/(x^2-2x+1)