What is expand (pi(17sqrt(17)-1))/(96) ?

The solution to expand (pi(17sqrt(17)-1))/(96) is (17sqrt(17)pi)/(96)-pi/(96)

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expand (pi(17sqrt(17)-1))/(96)

expand

\frac{π ( 17 17 - 1 )}{96}

\frac{17 17 π}{96} - \frac{π}{96}

Solution steps

\frac{π ( 17 17 - 1 )}{96}

Expand

π (1717 - 1) : 1717 π - π

= \frac{17 17 π - π}{96}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{17 17 π - π}{96} = \frac{17 17 π}{96} - \frac{π}{96}

= \frac{17 17 π}{96} - \frac{π}{96}

- \frac{2}{( s + 3 ) ^{3}}

m + 6 m - 6

(1, 3) (- 2, x - 2)

x ln^{2} (3 x) - 2 (x ln (3 x) - x)

\frac{( 2 x + 3 ) ( 3 - x )}{( 2 x + 1 ) ^{2}}

What is expand (pi(17sqrt(17)-1))/(96) ?
The solution to expand (pi(17sqrt(17)-1))/(96) is (17sqrt(17)pi)/(96)-pi/(96)