What are the solutions to the equation 35^2+12^2=x^2 ?

The solutions to the equation 35^2+12^2=x^2 are x=37,x=-37

Find the zeros of 35^2+12^2=x^2

The zeros of 35^2+12^2=x^2 are x=37,x=-37

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3 5^{2} + 1 2^{2} = x^{2}

x = 37, x = - 37

Solution steps

3 5^{2} + 1 2^{2} = x^{2}

Switch sides

x^{2} = 3 5^{2} + 1 2^{2}

Simplify

3 5^{2} + 1 2^{2} : 1369

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1369, x = - 1369

1369 = 37

- 1369 = - 37

x = 37, x = - 37

\frac{10}{3 + 2 x} \leq 5

(1 + 4 i) (1 - 4 i)

5 z^{2} + 14 z - 3 = 0

x^{2} + 11 x y + 30 y^{2}

- 14 = - (- 2 x + 2)

What are the solutions to the equation 35^2+12^2=x^2 ?
The solutions to the equation 35^2+12^2=x^2 are x=37,x=-37
Find the zeros of 35^2+12^2=x^2
The zeros of 35^2+12^2=x^2 are x=37,x=-37