What are the solutions to the equation 5z^2+14z-3=0 ?

The solutions to the equation 5z^2+14z-3=0 are z= 1/5 ,z=-3

Find the zeros of 5z^2+14z-3=0

The zeros of 5z^2+14z-3=0 are z= 1/5 ,z=-3

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5 z^{2} + 14 z - 3 = 0

z = \frac{1}{5}, z = - 3

Solution steps

5 z^{2} + 14 z - 3 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 5 ( - 3 )}{2 \cdot 5}

1 4^{2} - 4 \cdot 5 (- 3) = 16

z_{1, 2} = \frac{- 14 \pm 16}{2 \cdot 5}

Separate the solutions

z_{1} = \frac{- 14 + 16}{2 \cdot 5}, z_{2} = \frac{- 14 - 16}{2 \cdot 5}

z = \frac{- 14 + 16}{2 \cdot 5} : \frac{1}{5}

z = \frac{- 14 - 16}{2 \cdot 5} : - 3

The solutions to the quadratic equation are:

z = \frac{1}{5}, z = - 3

x^{2} + 11 x y + 30 y^{2}

- 14 = - (- 2 x + 2)

12 x^{2} - 64 = 0

∣ 6 m + 4 ∣ = 9

4 y^{4} - 100 y^{2}

What are the solutions to the equation 5z^2+14z-3=0 ?
The solutions to the equation 5z^2+14z-3=0 are z= 1/5 ,z=-3
Find the zeros of 5z^2+14z-3=0
The zeros of 5z^2+14z-3=0 are z= 1/5 ,z=-3