What are the solutions to the equation 12x^2-64=0 ?

The solutions to the equation 12x^2-64=0 are x= 4/(sqrt(3)),x=-4/(sqrt(3))

Find the zeros of 12x^2-64=0

The zeros of 12x^2-64=0 are x= 4/(sqrt(3)),x=-4/(sqrt(3))

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12 x^{2} - 64 = 0

x = \frac{4}{3}, x = - \frac{4}{3}

Solution steps

12 x^{2} - 64 = 0

Move

64

to the right side

12 x^{2} = 64

Divide both sides by

12

x^{2} = \frac{16}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{16}{3}, x = - \frac{16}{3}

\frac{16}{3} = \frac{4}{3}

- \frac{16}{3} = - \frac{4}{3}

x = \frac{4}{3}, x = - \frac{4}{3}

∣ 6 m + 4 ∣ = 9

4 y^{4} - 100 y^{2}

0 = (x - 5)^{2} + 2

- 16 \leq 5 x - 6 \leq 10

\frac{3}{5} x = \frac{23}{7}

What are the solutions to the equation 12x^2-64=0 ?
The solutions to the equation 12x^2-64=0 are x= 4/(sqrt(3)),x=-4/(sqrt(3))
Find the zeros of 12x^2-64=0
The zeros of 12x^2-64=0 are x= 4/(sqrt(3)),x=-4/(sqrt(3))