What is expand ((x+2)(y-1))/((x-3)(y+1)) ?

The solution to expand ((x+2)(y-1))/((x-3)(y+1)) is (xy-x+2y-2)/(xy+x-3y-3)

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expand ((x+2)(y-1))/((x-3)(y+1))

expand

\frac{( x + 2 ) ( y - 1 )}{( x - 3 ) ( y + 1 )}

\frac{x y - x + 2 y - 2}{x y + x - 3 y - 3}

Solution steps

\frac{( x + 2 ) ( y - 1 )}{( x - 3 ) ( y + 1 )}

Expand

(x - 3) (y + 1) : x y + x - 3 y - 3

= \frac{( x + 2 ) ( y - 1 )}{x y + x - 3 y - 3}

Expand

(x + 2) (y - 1) : x y - x + 2 y - 2

= \frac{x y - x + 2 y - 2}{x y + x - 3 y - 3}

\frac{x ^{2} + 7 x + 9}{( x + 1 ) ( x - 1 )}

(3 i, - i) (i, 8 i)

(x + 5) \circ (x - 3)

(5 x - 2 y) y^{'} (x) + x - y

20 π (x + 4)^{2}

What is expand ((x+2)(y-1))/((x-3)(y+1)) ?
The solution to expand ((x+2)(y-1))/((x-3)(y+1)) is (xy-x+2y-2)/(xy+x-3y-3)