What is the d/(dy)((x)(x+y)^2) ?

The d/(dy)((x)(x+y)^2) is 2x(x+y)

What is the first d/(dy)((x)(x+y)^2) ?

The first d/(dy)((x)(x+y)^2) is 2x(x+y)

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\frac{d}{d y} ((x) (x + y)^{2})

2 x (x + y)

Solution steps

\frac{d}{d y} ((x) (x + y)^{2})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{d}{d y} ((x + y)^{2})

Apply the chain rule:

2 (x + y) \frac{d}{d y} (x + y)

= 2 (x + y) \frac{d}{d y} (x + y)

\frac{d}{d y} (x + y) = 1

= x \cdot 2 (x + y) \cdot 1

Simplify

= 2 x (x + y)

(f \circ g) x (3 x - 4) + 2

(2 x + 3) e^{5 x}

(16 x^{2} + 40 x + 25) ln (x)

\frac{1}{( x - 2 ) ( x + 3 )}

\frac{x ^{3}}{( 3 x - 2 ) ^{2}}