What is expand-3x(c_{1}(2xln(x)+x)) ?

The solution to expand-3x(c_{1}(2xln(x)+x)) is -6c_{1}x^2ln(x)-3c_{1}x^2

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expand-3x(c_{1}(2xln(x)+x))

expand

- 3 x (c_{1} (2 x ln (x) + x))

- 6 c_{1} x^{2} ln (x) - 3 c_{1} x^{2}

Solution steps

- 3 x (c_{1} (2 x ln (x) + x))

Remove parentheses:

(a) = a

= - 3 x c_{1} (2 x ln (x) + x)

= - 3 c_{1} x (2 x ln (x) + x)

Apply the distributive law:

a (b + c) = ab + a c

a = - 3 x c_{1}, b = 2 x ln (x), c = x

= - 3 x c_{1} \cdot 2 x ln (x) + (- 3 x c_{1}) x

Apply minus-plus rules

+ (- a) = - a

= - 3 \cdot 2 c_{1} xx ln (x) - 3 c_{1} xx

Simplify

- 3 \cdot 2 c_{1} xx ln (x) - 3 c_{1} xx : - 6 c_{1} x^{2} ln (x) - 3 c_{1} x^{2}

= - 6 c_{1} x^{2} ln (x) - 3 c_{1} x^{2}

\frac{s ^{3} + 1}{s ( s - 1 ) ^{3}}

e^{((- 3 + 5 \cdot I) \cdot x)}

\frac{2 ( ab + a c + b c )}{ab c}

\frac{( 2 x ) !}{x ! ^{2} ( x + 1 )}

4 x 4 - 3 x 2 + 2 x

What is expand-3x(c_{1}(2xln(x)+x)) ?
The solution to expand-3x(c_{1}(2xln(x)+x)) is -6c_{1}x^2ln(x)-3c_{1}x^2