What is expand 4(2x-3=8(2x+5)) ?

The solution to expand 4(2x-3=8(2x+5)) is 8x-12=16x+40

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expand 4(2x-3=8(2x+5))

expand

4 (2 x - 3 = 8 (2 x + 5))

8 x - 12 = 16 x + 40

Solution steps

4 (2 x - 3 = 8 (2 x + 5))

= 4 (2 x - 3 \cdot 8 = (2 x + 5))

Apply the distributive law:

a (b - c) = ab - a c

a = 4, b = 2 x, c = 3 = 8 (2 x + 5)

4 \cdot 2 x - 4 \cdot 3 = 8 (2 x + 5)

Simplify

4 \cdot 2 x - 4 \cdot 3 = 8 (2 x + 5) : 8 x - 12 = 16 x + 40

8 x - 12 = 16 x + 40

\frac{( 6 x - 1 ) ^{3}}{18}

(- 3, - 1) P (- 6 - 3)

ln (3) (x - 5)

- \frac{7 ( 5 - 2 x )}{25 - 4 x}

\frac{( 5 x + 3 ) ( 5 x - 3 )}{25}

What is expand 4(2x-3=8(2x+5)) ?
The solution to expand 4(2x-3=8(2x+5)) is 8x-12=16x+40