What is expand-pisin(t)cos(t)(u-1) ?

The solution to expand-pisin(t)cos(t)(u-1) is -piusin(t)cos(t)+pisin(t)cos(t)

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expand-pisin(t)cos(t)(u-1)

expand

- π sin (t) cos (t) (u - 1)

- π u sin (t) cos (t) + π sin (t) cos (t)

Solution steps

- π sin (t) cos (t) (u - 1)

Apply the distributive law:

a (b - c) = ab - a c

a = - π sin (t) cos (t), b = u, c = 1

= - π sin (t) cos (t) u - (- π sin (t) cos (t)) \cdot 1

Apply minus-plus rules

- (- a) = a

= - π u sin (t) cos (t) + 1 π sin (t) cos (t)

Multiply:

1 π = π

= - π u sin (t) cos (t) + π sin (t) cos (t)

- \frac{3 n ^{2} ( n + 1 ) ^{2}}{2}

π (x^{2} + 6 x + 3)^{2}

\frac{( x + 2 )}{2} + (x + 2)

(5 x + 6 y = 20,) (8 x - 6 y = - 46)

\frac{5 ( x ^{2} - 3 )}{x - 1}

What is expand-pisin(t)cos(t)(u-1) ?
The solution to expand-pisin(t)cos(t)(u-1) is -piusin(t)cos(t)+pisin(t)cos(t)