What is expand (9(x-1)^2)/((3x-1)^2) ?

The solution to expand (9(x-1)^2)/((3x-1)^2) is (9x^2-18x+9)/(9x^2-6x+1)

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expand (9(x-1)^2)/((3x-1)^2)

expand

\frac{9 ( x - 1 ) ^{2}}{( 3 x - 1 ) ^{2}}

\frac{9 x ^{2} - 18 x + 9}{9 x ^{2} - 6 x + 1}

Solution steps

\frac{9 ( x - 1 ) ^{2}}{( 3 x - 1 ) ^{2}}

(3 x - 1)^{2} = 9 x^{2} - 6 x + 1

= \frac{9 ( x - 1 ) ^{2}}{9 x ^{2} - 6 x + 1}

(x - 1)^{2} = x^{2} - 2 x + 1

= \frac{9 ( x ^{2} - 2 x + 1 )}{9 x ^{2} - 6 x + 1}

Expand

9 (x^{2} - 2 x + 1) : 9 x^{2} - 18 x + 9

= \frac{9 x ^{2} - 18 x + 9}{9 x ^{2} - 6 x + 1}

\frac{π x ^{2} ( 6 - x )}{3} - 26

\frac{s}{( s - 1 ) ^{4}}

2 - 3 (x + Δ x)

\frac{1 - 6 x}{x ^{2} ( 2 x - 1 )}

30 (4 x^{5} + x)^{29} (20 x^{4} + 1)

What is expand (9(x-1)^2)/((3x-1)^2) ?
The solution to expand (9(x-1)^2)/((3x-1)^2) is (9x^2-18x+9)/(9x^2-6x+1)