What is expand (7x+3)/((x-4)(x-2)) ?

The solution to expand (7x+3)/((x-4)(x-2)) is (7x+3)/(x^2-6x+8)

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expand (7x+3)/((x-4)(x-2))

expand

\frac{7 x + 3}{( x - 4 ) ( x - 2 )}

\frac{7 x + 3}{x ^{2} - 6 x + 8}

Solution steps

\frac{7 x + 3}{( x - 4 ) ( x - 2 )}

Expand

(x - 4) (x - 2) : x^{2} - 6 x + 8

= \frac{7 x + 3}{x ^{2} - 6 x + 8}

\frac{( s + 3 )}{s ^{3} ( s - 2 ) ^{2}}

e^{2 (l n (y) + c)}

- 14 + 3 (x + 10 = 7 (2 x + 4) + x)

\frac{3 ( - 1 + 6 )}{5}

d x (x^{2} + 2 x + 1)

What is expand (7x+3)/((x-4)(x-2)) ?
The solution to expand (7x+3)/((x-4)(x-2)) is (7x+3)/(x^2-6x+8)