What is expand-14+3(x+10=7(2x+4)+x) ?

The solution to expand-14+3(x+10=7(2x+4)+x) is 3x+16=17x+28

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expand-14+3(x+10=7(2x+4)+x)

expand

- 14 + 3 (x + 10 = 7 (2 x + 4) + x)

3 x + 16 = 17 x + 28

Solution steps

- 14 + 3 (x + 10 = 7 (2 x + 4) + x)

= - 14 + 3 (x + 10 \cdot 7 = (2 x + 4) + x)

Expand

3 (x + 10 = 7 (2 x + 4) + x) : 3 x + 30 = 17 x + 28

- 14 + 3 x + 30 = 17 x + 28

Expand

- 14 + 3 x + 30 : 3 x + 16

3 x + 16 = 17 x + 28

\frac{3 ( - 1 + 6 )}{5}

d x (x^{2} + 2 x + 1)

(e^{- x} + 2) (e^{- x} + 4)

x^{2} + (y + 2)^{2}

(- 9 x + 4 y = 6, 9) (x + 5 y = - 33)

What is expand-14+3(x+10=7(2x+4)+x) ?
The solution to expand-14+3(x+10=7(2x+4)+x) is 3x+16=17x+28