What is expand-4(x+Δx)^2 ?

The solution to expand-4(x+Δx)^2 is -4x^2-8Δx^2-4Δ^2x^2

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expand-4(x+Δx)^2

expand

- 4 (x + Δ x)^{2}

- 4 x^{2} - 8Δ x^{2} - 4 Δ^{2} x^{2}

Solution steps

- 4 (x + Δ x)^{2}

(x + Δ x)^{2} = x^{2} + 2Δ x^{2} + Δ^{2} x^{2}

= - 4 (x^{2} + 2Δ x^{2} + Δ^{2} x^{2})

Distribute parentheses

= (- 4) x^{2} + (- 4) \cdot 2Δ x^{2} + (- 4) Δ^{2} x^{2}

Apply minus-plus rules

+ (- a) = - a

= - 4 x^{2} - 4 \cdot 2Δ x^{2} - 4 Δ^{2} x^{2}

Multiply the numbers:

4 \cdot 2 = 8

= - 4 x^{2} - 8Δ x^{2} - 4 Δ^{2} x^{2}

(1 + e^{4 x})^{2}

- \frac{3 x}{h ^{2} ( x + h )}

T (3, - 4, 5)

- \frac{( t ^{2} + 1 ) ^{2}}{4 t}

p oss ib l e \frac{1}{3} (3 j + 6)

What is expand-4(x+Δx)^2 ?
The solution to expand-4(x+Δx)^2 is -4x^2-8Δx^2-4Δ^2x^2