What is the d/(dt)((t)(-kt+70k)) ?

The d/(dt)((t)(-kt+70k)) is -2kt+70k

What is the first d/(dt)((t)(-kt+70k)) ?

The first d/(dt)((t)(-kt+70k)) is -2kt+70k

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\frac{d}{d t} ((t) (- k t + 70 k))

- 2 k t + 70 k

Solution steps

\frac{d}{d t} ((t) (- k t + 70 k))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = t, g = - k t + 70 k

= \frac{d t}{d t} (- k t + 70 k) + \frac{d}{d t} (- k t + 70 k) t

\frac{d t}{d t} = 1

\frac{d}{d t} (- k t + 70 k) = - k

= 1 \cdot (- k t + 70 k) + (- k) t

Simplify

1 \cdot (- k t + 70 k) + (- k) t : - 2 k t + 70 k

= - 2 k t + 70 k

33 - 126

Δ x (x + Δ x^{2}) + x^{2}

l im x \Rightarrow 2 (2 (x + 2) 2 - x)

(- y^{'} (t) + 1)^{2}

4 f^{'} (- 1) (3 x + 4)

What is the d/(dt)((t)(-kt+70k)) ?
The d/(dt)((t)(-kt+70k)) is -2kt+70k
What is the first d/(dt)((t)(-kt+70k)) ?
The first d/(dt)((t)(-kt+70k)) is -2kt+70k