What is (e^{iθ}-1)^2 ?

The solution to (e^{iθ}-1)^2 is (cos(θ)+isin(θ)-1)^2

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simplify (e^{iθ}-1)^2

simplify

(e^{i θ} - 1)^{2}

(cos (θ) + i sin (θ) - 1)^{2}

Solution steps

(e^{i θ} - 1)^{2}

Apply imaginary number rule:

e^{ia} = cos (a) + i sin (a)

= (cos (θ) + i sin (θ) - 1)^{2}

6 x + 4 y + 5 x

(x + 2) (x + 8)^{'}

dd x (9 x^{2} - 9 x - 3)

5 (r + 9) - 2 (1 - r = 1)

\frac{2 x + 24}{( x + 3 ) ( x + 4 ) ( x + 5 )}