What is expand ((x+2)(x-4))/((x-1)^2) ?

The solution to expand ((x+2)(x-4))/((x-1)^2) is (x^2-2x-8)/(x^2-2x+1)

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expand ((x+2)(x-4))/((x-1)^2)

expand

\frac{( x + 2 ) ( x - 4 )}{( x - 1 ) ^{2}}

\frac{x ^{2} - 2 x - 8}{x ^{2} - 2 x + 1}

Solution steps

\frac{( x + 2 ) ( x - 4 )}{( x - 1 ) ^{2}}

(x - 1)^{2} = x^{2} - 2 x + 1

= \frac{( x + 2 ) ( x - 4 )}{x ^{2} - 2 x + 1}

Expand

(x + 2) (x - 4) : x^{2} - 2 x - 8

= \frac{x ^{2} - 2 x - 8}{x ^{2} - 2 x + 1}

(3 y^{2} - 20 x^{2} y) d y

\frac{4}{( x - 1 ) ^{2} ( x - 3 ) ( x + 1 )}

\frac{( x - 1 ) z}{2 z - 4 t + 1}

- \frac{1}{2 ( 5 + 4 s - s ^{2} )}

\frac{( x ^{2} + 7 ) ^{2}}{x ^{5}}

What is expand ((x+2)(x-4))/((x-1)^2) ?
The solution to expand ((x+2)(x-4))/((x-1)^2) is (x^2-2x-8)/(x^2-2x+1)