What is expand 2/3 (3x+9=-2)(2x+6) ?

The solution to expand 2/3 (3x+9=-2)(2x+6) is 4x^2+12x+6=-(8x)/3-4

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expand 2/3 (3x+9=-2)(2x+6)

expand

\frac{2}{3} (3 x + 9 = - 2) (2 x + 6)

4 x^{2} + 12 x + 6 = - \frac{8 x}{3} - 4

Solution steps

\frac{2}{3} (3 x + 9 = - 2) (2 x + 6)

Expand

(3 x + 9 = - 2) (2 x + 6) : 6 x^{2} + 18 x + 9 = - 4 x - 6

= \frac{2}{3} (6 x^{2} + 18 x + 9 = - 4 x - 6)

Expand

\frac{2}{3} (6 x^{2} + 18 x + 9 = - 4 x - 6) : 4 x^{2} + 12 x + 6 = - \frac{8 x}{3} - 4

4 x^{2} + 12 x + 6 = - \frac{8 x}{3} - 4

\frac{( x - 5 ) ( x + 1 ) ( x - 1 )}{3 x + 2}

(- \frac{1}{x ^{2}})^{8}

P (8, - 7) Q (13, 7)

\frac{3}{4 ( 28 x + 16 y - 20 )}

- 4 x [c (x - c)^{2}]

What is expand 2/3 (3x+9=-2)(2x+6) ?
The solution to expand 2/3 (3x+9=-2)(2x+6) is 4x^2+12x+6=-(8x)/3-4