What is expand (2(x^2-9))/(x-4) ?

The solution to expand (2(x^2-9))/(x-4) is (2x^2-18)/(x-4)

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expand (2(x^2-9))/(x-4)

expand

\frac{2 ( x ^{2} - 9 )}{x - 4}

\frac{2 x ^{2} - 18}{x - 4}

Solution steps

\frac{2 ( x ^{2} - 9 )}{x - 4}

Expand

2 (x^{2} - 9) : 2 x^{2} - 18

= \frac{2 x ^{2} - 18}{x - 4}

\frac{6 a x}{( x + 2 ) ^{6}}

\frac{( 2 x - 7 ) ( 2 x + 7 )}{4}

(4 x) (5 x)

\frac{10 ( - j sin ( n wt ) - 1 )}{j w n}

\frac{1}{( s + 1 ) ( s ^{2} + 3 + 4 s )}

What is expand (2(x^2-9))/(x-4) ?
The solution to expand (2(x^2-9))/(x-4) is (2x^2-18)/(x-4)