What is expand ((e^{2y}-y)dy)/(e^y) ?

The solution to expand ((e^{2y}-y)dy)/(e^y) is e^ydy-(ydy)/(e^y)

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expand ((e^{2y}-y)dy)/(e^y)

expand

\frac{( e ^{2 y} - y ) d y}{e ^{y}}

e^{y} d y - \frac{y d y}{e ^{y}}

Solution steps

\frac{( e ^{2 y} - y ) d y}{e ^{y}}

Expand

(e^{2 y} - y) d y : e^{2 y} d y - y d y

= \frac{e ^{2 y} d y - y d y}{e ^{y}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{e ^{2 y} d y - y d y}{e ^{y}} = \frac{e ^{2 y} d y}{e ^{y}} - \frac{y d y}{e ^{y}}

= \frac{e ^{2 y} d y}{e ^{y}} - \frac{y d y}{e ^{y}}

Cancel

\frac{e ^{2 y} d y}{e ^{y}} : e^{y} d y

= e^{y} d y - \frac{y d y}{e ^{y}}

a (3, - 6) y b (- 7, - 10)

\frac{1}{x ^{2} ( x - y )}

(x + 2 y - 5 = 0) (4 x + 2 y + 3)

\frac{3}{x ^{- 2}}

- 2 (5 m + 4 = 12)

What is expand ((e^{2y}-y)dy)/(e^y) ?
The solution to expand ((e^{2y}-y)dy)/(e^y) is e^ydy-(ydy)/(e^y)