What is expand-(8(2-2x)^3)/3 ?

The solution to expand-(8(2-2x)^3)/3 is (64x^3)/3-64x^2+64x-64/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-(8(2-2x)^3)/3

expand

- \frac{8 ( 2 - 2 x ) ^{3}}{3}

\frac{64 x ^{3}}{3} - 64 x^{2} + 64 x - \frac{64}{3}

Solution steps

- \frac{8 ( 2 - 2 x ) ^{3}}{3}

(2 - 2 x)^{3} = 8 - 24 x + 24 x^{2} - 8 x^{3}

= - \frac{8 ( - 8 x ^{3} + 24 x ^{2} - 24 x + 8 )}{3}

Expand

8 (8 - 24 x + 24 x^{2} - 8 x^{3}) : 64 - 192 x + 192 x^{2} - 64 x^{3}

= - \frac{- 64 x ^{3} + 192 x ^{2} - 192 x + 64}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{64 - 192 x + 192 x ^{2} - 64 x ^{3}}{3} = - (\frac{64}{3}) - (- \frac{192 x}{3}) - (\frac{192 x ^{2}}{3}) - (- \frac{64 x ^{3}}{3})

= - (\frac{64}{3}) - (- \frac{192 x}{3}) - (\frac{192 x ^{2}}{3}) - (- \frac{64 x ^{3}}{3})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{64}{3} + \frac{192 x}{3} - \frac{192 x ^{2}}{3} + \frac{64 x ^{3}}{3}

Divide the numbers:

\frac{192}{3} = 64

= - \frac{64}{3} + 64 x - 64 x^{2} + \frac{64 x ^{3}}{3}

Rewrite in standard form

= \frac{64 x ^{3}}{3} - 64 x^{2} + 64 x - \frac{64}{3}

d x (25 x^{2} + 9)

\frac{k ( s + z )}{s ( s + 1 )}

\frac{( 2 n + 1 ) ^{2}}{( 2 n - 2 ) 2}

9 (x = 3)^{7} + 5 (x + 3) 4 + 2 (x + 3)

2 (e^{5} - e^{2})

What is expand-(8(2-2x)^3)/3 ?
The solution to expand-(8(2-2x)^3)/3 is (64x^3)/3-64x^2+64x-64/3