What is expand ((2n+1)^2)/((2n-2)2) ?

The solution to expand ((2n+1)^2)/((2n-2)2) is (4n^2+4n+1)/(4n-4)

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expand ((2n+1)^2)/((2n-2)2)

expand

\frac{( 2 n + 1 ) ^{2}}{( 2 n - 2 ) 2}

\frac{4 n ^{2} + 4 n + 1}{4 n - 4}

Solution steps

\frac{( 2 n + 1 ) ^{2}}{( 2 n - 2 ) \cdot 2}

(2 n + 1)^{2} = 4 n^{2} + 4 n + 1

= \frac{4 n ^{2} + 4 n + 1}{2 ( 2 n - 2 )}

Expand

(2 n - 2) \cdot 2 : 4 n - 4

= \frac{4 n ^{2} + 4 n + 1}{4 n - 4}

9 (x = 3)^{7} + 5 (x + 3) 4 + 2 (x + 3)

2 (e^{5} - e^{2})

18 π (\frac{π}{12} - \frac{1}{4})

h (x) in v ers a (9 - 2 x)

\frac{( 2 x ( 200 - 4 x ) )}{3}

What is expand ((2n+1)^2)/((2n-2)2) ?
The solution to expand ((2n+1)^2)/((2n-2)2) is (4n^2+4n+1)/(4n-4)