What is expand-2(2x-6+1=17-4x) ?

The solution to expand-2(2x-6+1=17-4x) is -4x+10=17+8x

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expand-2(2x-6+1=17-4x)

expand

- 2 (2 x - 6 + 1 = 17 - 4 x)

- 4 x + 10 = 17 + 8 x

Solution steps

- 2 (2 x - 6 + 1 = 17 - 4 x)

= - 2 (2 x - 6 + 1 \cdot 17 = - 4 x)

Distribute parentheses

(- 2) \cdot 2 x + (- 2) (- 6) + (- 2) \cdot 1 = 17 + (- 2) (- 4 x)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

- 2 \cdot 2 x + 2 \cdot 6 - 2 \cdot 1 = 17 + 2 \cdot 4 x

Simplify

- 2 \cdot 2 x + 2 \cdot 6 - 2 \cdot 1 = 17 + 2 \cdot 4 x : - 4 x + 10 = 17 + 8 x

- 4 x + 10 = 17 + 8 x

\frac{( y - 1 ) ( 2 x z + 1 )}{y}

- \frac{4}{25} (5 e^{5 x} x - e^{5 x})

\frac{( 2 + h ^{3} ) - 8}{h}

(x - 9 = - y^{2}) 1

What is expand-2(2x-6+1=17-4x) ?
The solution to expand-2(2x-6+1=17-4x) is -4x+10=17+8x