What is expand ((4x+1)(2x-3))/4 ?

The solution to expand ((4x+1)(2x-3))/4 is 2x^2-(5x)/2-3/4

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expand ((4x+1)(2x-3))/4

expand

\frac{( 4 x + 1 ) ( 2 x - 3 )}{4}

2 x^{2} - \frac{5 x}{2} - \frac{3}{4}

Solution steps

\frac{( 4 x + 1 ) ( 2 x - 3 )}{4}

Expand

(4 x + 1) (2 x - 3) : 8 x^{2} - 10 x - 3

= \frac{8 x ^{2} - 10 x - 3}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{8 x ^{2} - 10 x - 3}{4} = \frac{8 x ^{2}}{4} - \frac{10 x}{4} - \frac{3}{4}

= \frac{8 x ^{2}}{4} - \frac{10 x}{4} - \frac{3}{4}

Divide the numbers:

\frac{8}{4} = 2

= 2 x^{2} - \frac{10 x}{4} - \frac{3}{4}

Cancel

\frac{10 x}{4} : \frac{5 x}{2}

= 2 x^{2} - \frac{5 x}{2} - \frac{3}{4}

\frac{( 2 k + 1 ) ( k + 1 ) ( k )}{6}

4 (sec^{2} (x^{2} + 3 x + 2) (2 x + 3))

e^{(4 t)} (t^{2} + 3 t + 5)

\frac{2 x ^{3} d x}{( x ^{2} + 1 ) ^{2}}

(- 3 x^{3} - 8 x^{6}) (10 e^{x} + 2)

What is expand ((4x+1)(2x-3))/4 ?
The solution to expand ((4x+1)(2x-3))/4 is 2x^2-(5x)/2-3/4