What are the solutions to the equation 0=x^2-16x+60 ?

The solutions to the equation 0=x^2-16x+60 are x=10,x=6

Find the zeros of 0=x^2-16x+60

The zeros of 0=x^2-16x+60 are x=10,x=6

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0 = x^{2} - 16 x + 60

x = 10, x = 6

Solution steps

0 = x^{2} - 16 x + 60

Switch sides

x^{2} - 16 x + 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 60}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 60 = 4

x_{1, 2} = \frac{- ( - 16 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 4}{2 \cdot 1}

x = \frac{- ( - 16 ) + 4}{2 \cdot 1} : 10

x = \frac{- ( - 16 ) - 4}{2 \cdot 1} : 6

The solutions to the quadratic equation are:

x = 10, x = 6

- 5 + 8

5 x (4 - x) = 12

\frac{n ^{4} - 11 n ^{2} + 30}{n ^{4} - 7 n ^{2} + 10}

9 x^{2} - 76 x - 45

What are the solutions to the equation 0=x^2-16x+60 ?
The solutions to the equation 0=x^2-16x+60 are x=10,x=6
Find the zeros of 0=x^2-16x+60
The zeros of 0=x^2-16x+60 are x=10,x=6