What is (n^4-11n^2+30)/(n^4-7n^2+10) ?

The solution to (n^4-11n^2+30)/(n^4-7n^2+10) is (n^2-6)/(n^2-2)

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simplify (n^4-11n^2+30)/(n^4-7n^2+10)

simplify

\frac{n ^{4} - 11 n ^{2} + 30}{n ^{4} - 7 n ^{2} + 10}

\frac{n ^{2} - 6}{n ^{2} - 2}

Solution steps

\frac{n ^{4} - 11 n ^{2} + 30}{n ^{4} - 7 n ^{2} + 10}

Factor

n^{4} - 11 n^{2} + 30 : (n^{2} - 5) (n^{2} - 6)

= \frac{( n ^{2} - 5 ) ( n ^{2} - 6 )}{n ^{4} - 7 n ^{2} + 10}

Factor

n^{4} - 7 n^{2} + 10 : (n^{2} - 2) (n^{2} - 5)

= \frac{( n ^{2} - 5 ) ( n ^{2} - 6 )}{( n ^{2} - 2 ) ( n ^{2} - 5 )}

Cancel the common factor:

n^{2} - 5

= \frac{n ^{2} - 6}{n ^{2} - 2}

9 x^{2} - 76 x - 45

4 r^{2} + 2 r - 2 = 0

2 z^{2} + z = 6

\frac{2}{x - 1} \leq \frac{1}{2}

What is (n^4-11n^2+30)/(n^4-7n^2+10) ?
The solution to (n^4-11n^2+30)/(n^4-7n^2+10) is (n^2-6)/(n^2-2)