What is expand A(2,-1,3)B(1,-2,-3) ?

The solution to expand A(2,-1,3)B(1,-2,-3) is 2AB,1,-2AB,2,-2AB,3-1*AB,3*1,1,3*2,1,3*3

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expand A(2,-1,3)B(1,-2,-3)

expand

A (2, - 1, 3) B (1, - 2, - 3)

2 A B, 1, - 2 A B, 2, - 2 A B, 3 - 1 \cdot A B, 3 \cdot 1, 1, 3 \cdot 2, 1, 3 \cdot 3

Solution steps

A (2, - 1, 3) B (1, - 2, - 3)

= (2, - 1 \cdot 3,) (1, - 2, - 3) A B

Expand

(2, - 1, 3) (1, - 2, - 3) : 2, 1, - 2, 2, - 2, 3 - 1, 3 \cdot 1, 1, 3 \cdot 2, 1, 3 \cdot 3

= A B (2, 1, - 2, 2, - 2, 3 - 1, 3 \cdot 1, 1, 3 \cdot 2, 1, 3 \cdot 3)

Expand

A B (2, 1, - 2, 2, - 2, 3 - 1, 3 \cdot 1, 1, 3 \cdot 2, 1, 3 \cdot 3) : 2 A B, 1, - 2 A B, 2, - 2 A B, 3 - 1 \cdot A B, 3 \cdot 1, 1, 3 \cdot 2, 1, 3 \cdot 3

= 2 A B, 1, - 2 A B, 2, - 2 A B, 3 - 1 \cdot A B, 3 \cdot 1, 1, 3 \cdot 2, 1, 3 \cdot 3

e^{t} (- t e^{- t} - e^{- t})

\frac{2 s + 1}{( s ^{2} + 4 s + 3 ) ( s - 2 )}

\frac{d}{d t} ((x) (9 + sin (x)))

\frac{2 ( x + h ) + 3}{x + h - 1}

\frac{d x}{( 6 x + 1 ) ^{4}}

What is expand A(2,-1,3)B(1,-2,-3) ?
The solution to expand A(2,-1,3)B(1,-2,-3) is 2AB,1,-2AB,2,-2AB,3-1*AB,3*1,1,3*2,1,3*3