What is expand f'(x)(x+3)^2 ?

The solution to expand f'(x)(x+3)^2 is x^2f'(x)+6xf'(x)+9f'(x)

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expand f'(x)(x+3)^2

expand

f^{'} (x) (x + 3)^{2}

x^{2} f' (x) + 6 x f' (x) + 9 f' (x)

Solution steps

f^{'} (x) (x + 3)^{2}

(x + 3)^{2} = x^{2} + 6 x + 9

= f^{^{'}} (x) (x^{2} + 6 x + 9)

Distribute parentheses

= f^{^{'}} (x) x^{2} + f^{^{'}} (x) 6 x + f^{^{'}} (x) 9

= x^{2} f^{^{'}} (x) + 6 x f^{^{'}} (x) + 9 f^{^{'}} (x)

(y - 4) (y^{2} = + 4 y + 16)

e^{4 x} \cdot (e^{4 x} + 4 x e^{4 x})

e^{x} (- x^{2} + 7)

(x^{2} - x y) \frac{d y}{d x}

\frac{7 ( 373 - 7 )}{18}

What is expand f'(x)(x+3)^2 ?
The solution to expand f'(x)(x+3)^2 is x^2f'(x)+6xf'(x)+9f'(x)