What are the solutions to the equation 2z^2+z=6 ?

The solutions to the equation 2z^2+z=6 are z= 3/2 ,z=-2

Find the zeros of 2z^2+z=6

The zeros of 2z^2+z=6 are z= 3/2 ,z=-2

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2 z^{2} + z = 6

z = \frac{3}{2}, z = - 2

Decimal Notation

z = 1.5, z = - 2

Solution steps

2 z^{2} + z = 6

Move

6

to the left side

2 z^{2} + z - 6 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 6) = 7

z_{1, 2} = \frac{- 1 \pm 7}{2 \cdot 2}

Separate the solutions

z_{1} = \frac{- 1 + 7}{2 \cdot 2}, z_{2} = \frac{- 1 - 7}{2 \cdot 2}

z = \frac{- 1 + 7}{2 \cdot 2} : \frac{3}{2}

z = \frac{- 1 - 7}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

z = \frac{3}{2}, z = - 2

\frac{2}{x - 1} \leq \frac{1}{2}

3^{2} = 1. 5^{2} + x^{2}

(\frac{5}{4})^{- 3}

x^{2} - 4 > 0

(x + 2) (2 x - 3) = 5 x^{2} + x - 114

What are the solutions to the equation 2z^2+z=6 ?
The solutions to the equation 2z^2+z=6 are z= 3/2 ,z=-2
Find the zeros of 2z^2+z=6
The zeros of 2z^2+z=6 are z= 3/2 ,z=-2