What are the solutions to the equation (x+2)(2x-3)=5x^2+x-114 ?

The solutions to the equation (x+2)(2x-3)=5x^2+x-114 are x=6,x=-6

Find the zeros of (x+2)(2x-3)=5x^2+x-114

The zeros of (x+2)(2x-3)=5x^2+x-114 are x=6,x=-6

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(x + 2) (2 x - 3) = 5 x^{2} + x - 114

x = 6, x = - 6

Solution steps

(x + 2) (2 x - 3) = 5 x^{2} + x - 114

Expand

(x + 2) (2 x - 3) : 2 x^{2} + x - 6

2 x^{2} + x - 6 = 5 x^{2} + x - 114

Move

6

to the right side

2 x^{2} + x = 5 x^{2} + x - 108

Move

x

to the left side

2 x^{2} = 5 x^{2} - 108

Move

5 x^{2}

to the left side

- 3 x^{2} = - 108

Divide both sides by

- 3

x^{2} = 36

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 36, x = - 36

36 = 6

- 36 = - 6

x = 6, x = - 6

- x^{2} - 3 x - 2

\frac{y + 3}{y ^{2} + 1} > 1

10 x^{2} + 19 x - 15

\frac{3}{5} + \frac{1}{3} > 2

\frac{3}{4} x^{2} - 4 x - 3 = 0

What are the solutions to the equation (x+2)(2x-3)=5x^2+x-114 ?
The solutions to the equation (x+2)(2x-3)=5x^2+x-114 are x=6,x=-6
Find the zeros of (x+2)(2x-3)=5x^2+x-114
The zeros of (x+2)(2x-3)=5x^2+x-114 are x=6,x=-6