What is expand x/((x+1)(x^2-2x-5)) ?

The solution to expand x/((x+1)(x^2-2x-5)) is x/(x^3-x^2-7x-5)

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expand x/((x+1)(x^2-2x-5))

expand

\frac{x}{( x + 1 ) ( x ^{2} - 2 x - 5 )}

\frac{x}{x ^{3} - x ^{2} - 7 x - 5}

Solution steps

\frac{x}{( x + 1 ) ( x ^{2} - 2 x - 5 )}

Expand

(x + 1) (x^{2} - 2 x - 5) : x^{3} - x^{2} - 7 x - 5

= \frac{x}{x ^{3} - x ^{2} - 7 x - 5}

- \frac{( x - 1 ) ( x + 7 )}{15}

3 (5 y + 1 = 18 y)

\frac{1}{( x + 3 ) ( x + 4 ) ( x - 4 )}

\frac{x + 5}{( x + 9 ) ( x + 2 )}

2 (5 s + 3 = - 24)

What is expand x/((x+1)(x^2-2x-5)) ?
The solution to expand x/((x+1)(x^2-2x-5)) is x/(x^3-x^2-7x-5)