What is expand-((x-1)(x+7))/(15) ?

The solution to expand-((x-1)(x+7))/(15) is -(x^2}{15}-\frac{2x)/5+7/15

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expand-((x-1)(x+7))/(15)

expand

- \frac{( x - 1 ) ( x + 7 )}{15}

- \frac{x ^{2}}{15} - \frac{2 x}{5} + \frac{7}{15}

Solution steps

- \frac{( x - 1 ) ( x + 7 )}{15}

Expand

(x - 1) (x + 7) : x^{2} + 6 x - 7

= - \frac{x ^{2} + 6 x - 7}{15}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} + 6 x - 7}{15} = - (\frac{x ^{2}}{15}) - (\frac{6 x}{15}) - (- \frac{7}{15})

= - (\frac{x ^{2}}{15}) - (\frac{6 x}{15}) - (- \frac{7}{15})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{x ^{2}}{15} - \frac{6 x}{15} + \frac{7}{15}

Cancel

\frac{6 x}{15} : \frac{2 x}{5}

= - \frac{x ^{2}}{15} - \frac{2 x}{5} + \frac{7}{15}

3 (5 y + 1 = 18 y)

\frac{1}{( x + 3 ) ( x + 4 ) ( x - 4 )}

\frac{x + 5}{( x + 9 ) ( x + 2 )}

2 (5 s + 3 = - 24)

(e^{x} x - e^{x} + 5 - 2 e) (2 x - 1)

What is expand-((x-1)(x+7))/(15) ?
The solution to expand-((x-1)(x+7))/(15) is -(x^2}{15}-\frac{2x)/5+7/15