What are the solutions to the equation 3/4 x^2-4x-3=0 ?

The solutions to the equation 3/4 x^2-4x-3=0 are x=6,x=-2/3

Find the zeros of 3/4 x^2-4x-3=0

The zeros of 3/4 x^2-4x-3=0 are x=6,x=-2/3

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\frac{3}{4} x^{2} - 4 x - 3 = 0

x = 6, x = - \frac{2}{3}

Decimal Notation

x = 6, x = - 0.66666 \dots

Solution steps

\frac{3}{4} x^{2} - 4 x - 3 = 0

Multiply both sides by

4

3 x^{2} - 16 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 3 ( - 12 )}{2 \cdot 3}

(- 16)^{2} - 4 \cdot 3 (- 12) = 20

x_{1, 2} = \frac{- ( - 16 ) \pm 20}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 20}{2 \cdot 3}, x_{2} = \frac{- ( - 16 ) - 20}{2 \cdot 3}

x = \frac{- ( - 16 ) + 20}{2 \cdot 3} : 6

x = \frac{- ( - 16 ) - 20}{2 \cdot 3} : - \frac{2}{3}

The solutions to the quadratic equation are:

x = 6, x = - \frac{2}{3}

6 x + 1 = 2 x + 1

\frac{4 x ^{2} y z ^{5}}{6 x ^{2} y ^{3} z ^{2}}

- 2 (8 x - 4) < 2 x + 5

c^{2} + 24 c + 135

9 = \frac{3}{2} (3 x + 4)

What are the solutions to the equation 3/4 x^2-4x-3=0 ?
The solutions to the equation 3/4 x^2-4x-3=0 are x=6,x=-2/3
Find the zeros of 3/4 x^2-4x-3=0
The zeros of 3/4 x^2-4x-3=0 are x=6,x=-2/3