What is expand-((pi+4)(1-sqrt(2)))/4 ?

The solution to expand-((pi+4)(1-sqrt(2)))/4 is -pi/4+pi/(2sqrt(2))-1+sqrt(2)

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expand-((pi+4)(1-sqrt(2)))/4

expand

- \frac{( π + 4 ) ( 1 - 2 )}{4}

- \frac{π}{4} + \frac{π}{2 2} - 1 + 2

Solution steps

- \frac{( π + 4 ) ( 1 - 2 )}{4}

Expand

(π + 4) (1 - 2) : π - 2 π + 4 - 42

= - \frac{π - 2 π + 4 - 4 2}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{π - 2 π + 4 - 4 2}{4} = - (\frac{π}{4}) - (- \frac{2 π}{4}) - (\frac{4}{4}) - (- \frac{4 2}{4})

= - (\frac{π}{4}) - (- \frac{2 π}{4}) - (\frac{4}{4}) - (- \frac{4 2}{4})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{π}{4} + \frac{2 π}{4} - \frac{4}{4} + \frac{4 2}{4}

Cancel

\frac{2 π}{4} : \frac{π}{2 2}

= - \frac{π}{4} + \frac{π}{2 2} - \frac{4}{4} + \frac{4 2}{4}

Apply rule

\frac{a}{a} = 1

= - \frac{π}{4} + \frac{π}{2 2} - 1 + \frac{4 2}{4}

Divide the numbers:

\frac{4}{4} = 1

= - \frac{π}{4} + \frac{π}{2 2} - 1 + 2

(x + y + z + 3)^{3}

\frac{1}{2 ( x - 2 ) ( 2 x - 3 ) ( 4 x + 7 )}

\frac{( 2 + θ ) ^{2}}{2}

\frac{d y}{x} (x^{2} + 16 y^{2} = 25)

(- 6 x - 7 y = 14) \cdot 3

What is expand-((pi+4)(1-sqrt(2)))/4 ?
The solution to expand-((pi+4)(1-sqrt(2)))/4 is -pi/4+pi/(2sqrt(2))-1+sqrt(2)