What is expand ((20d-at)^2)/(25t^2) ?

The solution to expand ((20d-at)^2)/(25t^2) is (16d^2)/(t^2)-(8da)/(5t)+(a^2)/(25)

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expand ((20d-at)^2)/(25t^2)

expand

\frac{( 20 d - a t ) ^{2}}{25 t ^{2}}

\frac{16 d ^{2}}{t ^{2}} - \frac{8 d a}{5 t} + \frac{a ^{2}}{25}

Solution steps

\frac{( 20 d - a t ) ^{2}}{25 t ^{2}}

(20 d - a t)^{2} = 400 d^{2} - 40 d a t + a^{2} t^{2}

= \frac{400 d ^{2} - 40 d a t + a ^{2} t ^{2}}{25 t ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{400 d ^{2} - 40 d a t + a ^{2} t ^{2}}{25 t ^{2}} = \frac{400 d ^{2}}{25 t ^{2}} - \frac{40 d a t}{25 t ^{2}} + \frac{a ^{2} t ^{2}}{25 t ^{2}}

= \frac{400 d ^{2}}{25 t ^{2}} - \frac{40 d a t}{25 t ^{2}} + \frac{a ^{2} t ^{2}}{25 t ^{2}}

Divide the numbers:

\frac{400}{25} = 16

= \frac{16 d ^{2}}{t ^{2}} - \frac{40 d a t}{25 t ^{2}} + \frac{a ^{2} t ^{2}}{25 t ^{2}}

Cancel

\frac{40 d a t}{25 t ^{2}} : \frac{8 d a}{5 t}

= \frac{16 d ^{2}}{t ^{2}} - \frac{8 d a}{5 t} + \frac{a ^{2} t ^{2}}{25 t ^{2}}

Cancel

\frac{a ^{2} t ^{2}}{25 t ^{2}} : \frac{a ^{2}}{25}

= \frac{16 d ^{2}}{t ^{2}} - \frac{8 d a}{5 t} + \frac{a ^{2}}{25}

\frac{( - 5 + x ) ( 5 + x )}{4 + 5 x}

\frac{s + 1}{s ( s ^{2} + 1 )}

- 4 (x - 3 y = 4)

\frac{( 3 s + 4 ) ^{3}}{9}

\frac{2 - x ( x + 2 + 2 )}{x - 2}

What is expand ((20d-at)^2)/(25t^2) ?
The solution to expand ((20d-at)^2)/(25t^2) is (16d^2)/(t^2)-(8da)/(5t)+(a^2)/(25)