What is expand ((3x+1)(3x-1))/(5x^2) ?

The solution to expand ((3x+1)(3x-1))/(5x^2) is 9/5-1/(5x^2)

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expand ((3x+1)(3x-1))/(5x^2)

expand

\frac{( 3 x + 1 ) ( 3 x - 1 )}{5 x ^{2}}

\frac{9}{5} - \frac{1}{5 x ^{2}}

Solution steps

\frac{( 3 x + 1 ) ( 3 x - 1 )}{5 x ^{2}}

Expand

(3 x + 1) (3 x - 1) : 9 x^{2} - 1

= \frac{9 x ^{2} - 1}{5 x ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 x ^{2} - 1}{5 x ^{2}} = \frac{9 x ^{2}}{5 x ^{2}} - \frac{1}{5 x ^{2}}

= \frac{9 x ^{2}}{5 x ^{2}} - \frac{1}{5 x ^{2}}

Cancel

\frac{9 x ^{2}}{5 x ^{2}} : \frac{9}{5}

= \frac{9}{5} - \frac{1}{5 x ^{2}}

\frac{5}{( s + 3 ) ( s ^{2} + 25 )}

(\forall y) (\exists x) (x = y + 1)

\frac{x ^{2} ( x + 2 z )}{z \cdot y}

so l v e (2 x^{2} + 9 x - 5 = 0)

\frac{9 x ^{3}}{( x - 6 ) ^{2}}

What is expand ((3x+1)(3x-1))/(5x^2) ?
The solution to expand ((3x+1)(3x-1))/(5x^2) is 9/5-1/(5x^2)