What are the solutions to the equation x-x^2=0 ?

The solutions to the equation x-x^2=0 are x=0,x=1

Find the zeros of x-x^2=0

The zeros of x-x^2=0 are x=0,x=1

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x - x^{2} = 0

x = 0, x = 1

Solution steps

x - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

1^{2} - 4 (- 1) \cdot 0 = 1

x_{1, 2} = \frac{- 1 \pm 1}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1 + 1}{2 ( - 1 )}, x_{2} = \frac{- 1 - 1}{2 ( - 1 )}

x = \frac{- 1 + 1}{2 ( - 1 )} : 0

x = \frac{- 1 - 1}{2 ( - 1 )} : 1

The solutions to the quadratic equation are:

x = 0, x = 1

u^{2} + u - 2 = 0

\frac{3 ^{4}}{3 ^{8}}

5903 = P + P (6.4) (5)

∣ - 3 x - 2 ∣ = 5

What are the solutions to the equation x-x^2=0 ?
The solutions to the equation x-x^2=0 are x=0,x=1
Find the zeros of x-x^2=0
The zeros of x-x^2=0 are x=0,x=1