What is expand (2+x)[\H(x-2)-H[x-3]] ?

The solution to expand (2+x)[\H(x-2)-H[x-3]] is -x^2H+xH+x\H(x-2)+2\H(x-2)+6H

Popular >

expand (2+x)[\H(x-2)-H[x-3]]

expand

(2 + x) [H (x - 2) - H [x - 3]]

- x^{2} H + x H + x H (x - 2) + 2 H (x - 2) + 6 H

Solution steps

(2 + x) [H (x - 2) - H [x - 3]]

Apply the distributive law:

a (b + c) = ab + a c

a = [H (x - 2) - H [x - 3]], b = 2, c = x

= [H (x - 2) - H [x - 3]] \cdot 2 + [H (x - 2) - H [x - 3]] x

= 2 [H (x - 2) - H [x - 3]] + x [H (x - 2) - H [x - 3]]

Simplify

2 [H (x - 2) - H [x - 3]] + x [H (x - 2) - H [x - 3]] : - x^{2} H + x H + x H (x - 2) + 2 H (x - 2) + 6 H

= - x^{2} H + x H + x H (x - 2) + 2 H (x - 2) + 6 H

(d t + 3 t^{4} d w)^{2}

\frac{x ^{2} + x y + y ^{2}}{x y ( x - y )}

\frac{( 5 - 2 x ) ^{2}}{π} - x^{2}

(l, m, n) (1, - 4, - 2)

5^{3} \cdot 8^{4}

What is expand (2+x)[\H(x-2)-H[x-3]] ?
The solution to expand (2+x)[\H(x-2)-H[x-3]] is -x^2H+xH+x\H(x-2)+2\H(x-2)+6H