What is expand (a(e^{vx}-e^{-vx}))/(2x) ?

The solution to expand (a(e^{vx}-e^{-vx}))/(2x) is (ae^{vx})/(2x)-(ae^{-vx})/(2x)

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expand (a(e^{vx}-e^{-vx}))/(2x)

expand

\frac{a ( e ^{vx} - e ^{- vx} )}{2 x}

\frac{a e ^{vx}}{2 x} - \frac{a e ^{- vx}}{2 x}

Solution steps

\frac{a ( e ^{vx} - e ^{- vx} )}{2 x}

Expand

a (e^{vx} - e^{- vx}) : a e^{vx} - a e^{- vx}

= \frac{a e ^{vx} - a e ^{- vx}}{2 x}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{a e ^{vx} - a e ^{- vx}}{2 x} = \frac{a e ^{vx}}{2 x} - \frac{a e ^{- vx}}{2 x}

= \frac{a e ^{vx}}{2 x} - \frac{a e ^{- vx}}{2 x}

\frac{d}{d t} ((x) (b t + c t^{2}))

\frac{( 2 x + x ^{3} ) ^{3}}{12}

(y^{2} + 3 x) d x + (e^{x}) d y

(1, i) (2 - 1, 3 + 2 i)

\frac{( x + 3 ) ( 3 x + 1 + 1 )}{3}

What is expand (a(e^{vx}-e^{-vx}))/(2x) ?
The solution to expand (a(e^{vx}-e^{-vx}))/(2x) is (ae^{vx})/(2x)-(ae^{-vx})/(2x)