What is expand ((2x-1)(3x+2))/2 ?

The solution to expand ((2x-1)(3x+2))/2 is 3x^2+x/2-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((2x-1)(3x+2))/2

expand

\frac{( 2 x - 1 ) ( 3 x + 2 )}{2}

3 x^{2} + \frac{x}{2} - 1

Solution steps

\frac{( 2 x - 1 ) ( 3 x + 2 )}{2}

Expand

(2 x - 1) (3 x + 2) : 6 x^{2} + x - 2

= \frac{6 x ^{2} + x - 2}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{6 x ^{2} + x - 2}{2} = \frac{6 x ^{2}}{2} + \frac{x}{2} - \frac{2}{2}

= \frac{6 x ^{2}}{2} + \frac{x}{2} - \frac{2}{2}

Apply rule

\frac{a}{a} = 1

\frac{2}{2} = 1

= \frac{6 x ^{2}}{2} + \frac{x}{2} - 1

Divide the numbers:

\frac{6}{2} = 3

= 3 x^{2} + \frac{x}{2} - 1

(n - k - 1)! \cdot (n - k)

i e^{- (1 + i) t}

(x - e^{x} sin (y)) d y

x - 1 (1 - 6) - 6

\frac{u ( - 2 u - 3 )}{1 + 2 u}

What is expand ((2x-1)(3x+2))/2 ?
The solution to expand ((2x-1)(3x+2))/2 is 3x^2+x/2-1