What is expand-1(-3x^2+2x-5=0) ?

The solution to expand-1(-3x^2+2x-5=0) is 3x^2-2x+5=0

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expand-1(-3x^2+2x-5=0)

expand

- 1 (- 3 x^{2} + 2 x - 5 = 0)

3 x^{2} - 2 x + 5 = 0

Solution steps

- 1 \cdot (- 3 x^{2} + 2 x - 5 = 0)

= - 1 \cdot (- 3 x^{2} + 2 x - 5 \cdot 0 =)

Distribute parentheses

= (- 1) (- 3 x^{2}) + (- 1) \cdot 2 x + (- 1) (- 5 = 0)

Apply minus-plus rules

(- a) (- b) = ab, + (- a) = - a

1 \cdot 3 x^{2} - 1 \cdot 2 x + 1 \cdot 5 = 0

Expand

1 \cdot 3 x^{2} - 1 \cdot 2 x + 1 \cdot 5 : 3 x^{2} - 2 x + 5

3 x^{2} - 2 x + 5 = 0

(t e^{t y} cos (2 t) - 3) d t

(1 - 2 e^{2 x}) (3 x + e^{2 x})

\frac{2 c ^{2}}{( 2 - c ) ^{2}}

\frac{1}{x ^{2} ( x ^{2} - 4 ) ^{2}}

(0.685 = 805 x + 40 y) 60

What is expand-1(-3x^2+2x-5=0) ?
The solution to expand-1(-3x^2+2x-5=0) is 3x^2-2x+5=0