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Popular >

d/(dt)((x)(-By(x,t,B)+t))

Solution

\frac{d}{d t} ((x) (- B y (x, t, B) + t))

Solution

x (- B y (x,, B \cdot 1) + 1)

Solution steps

\frac{d}{d t} ((x) (- B y (x, t, B) + t))

Treat

x, B, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{d}{d t} (- B y (x, t, B) + t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= x (- \frac{d}{d t} (B y (x, t, B)) + \frac{d t}{d t})

\frac{d}{d t} (B y (x, t, B)) = B y (x,, B \cdot 1)

\frac{d t}{d t} = 1

= x (- B y (x,, B \cdot 1) + 1)

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expand 6(-4x+6y=-2)expand

6 (- 4 x + 6 y = - 2)

Frequently Asked Questions (FAQ)

What is the d/(dt)((x)(-By(x,t,B)+t)) ?
The d/(dt)((x)(-By(x,t,B)+t)) is x(-By(x,,B*1)+1)
What is the first d/(dt)((x)(-By(x,t,B)+t)) ?
The first d/(dt)((x)(-By(x,t,B)+t)) is x(-By(x,,B*1)+1)