What is expand ((n^2-4)^2)/(4n^2) ?

The solution to expand ((n^2-4)^2)/(4n^2) is (n^2)/4-2+4/(n^2)

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expand ((n^2-4)^2)/(4n^2)

expand

\frac{( n ^{2} - 4 ) ^{2}}{4 n ^{2}}

\frac{n ^{2}}{4} - 2 + \frac{4}{n ^{2}}

Solution steps

\frac{( n ^{2} - 4 ) ^{2}}{4 n ^{2}}

(n^{2} - 4)^{2} = n^{4} - 8 n^{2} + 16

= \frac{n ^{4} - 8 n ^{2} + 16}{4 n ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{n ^{4} - 8 n ^{2} + 16}{4 n ^{2}} = \frac{n ^{4}}{4 n ^{2}} - \frac{8 n ^{2}}{4 n ^{2}} + \frac{16}{4 n ^{2}}

= \frac{n ^{4}}{4 n ^{2}} - \frac{8 n ^{2}}{4 n ^{2}} + \frac{16}{4 n ^{2}}

Cancel

\frac{n ^{4}}{4 n ^{2}} : \frac{n ^{2}}{4}

= \frac{n ^{2}}{4} - \frac{8 n ^{2}}{4 n ^{2}} + \frac{16}{4 n ^{2}}

Cancel

\frac{8 n ^{2}}{4 n ^{2}} : 2

= \frac{n ^{2}}{4} - 2 + \frac{16}{4 n ^{2}}

Divide the numbers:

\frac{16}{4} = 4

= \frac{n ^{2}}{4} - 2 + \frac{4}{n ^{2}}

y (x + 1) d x - 5 d x

\frac{9 s - 31}{( s - 3 ) ( s - 4 )}

t (2 t, - 5, t^{2})

\frac{x ^{2} + 3 x - 16}{( x + 7 ) ( x + 5 )}

\frac{3 x + 4}{( x + 2 ) ^{2}}

What is expand ((n^2-4)^2)/(4n^2) ?
The solution to expand ((n^2-4)^2)/(4n^2) is (n^2)/4-2+4/(n^2)