What is expand ((3x^2+4x-3))/x ?

The solution to expand ((3x^2+4x-3))/x is 3x+4-3/x

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expand ((3x^2+4x-3))/x

expand

\frac{( 3 x ^{2} + 4 x - 3 )}{x}

3 x + 4 - \frac{3}{x}

Solution steps

\frac{3 x ^{2} + 4 x - 3}{x}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 x ^{2} + 4 x - 3}{x} = \frac{3 x ^{2}}{x} + \frac{4 x}{x} - \frac{3}{x}

= \frac{3 x ^{2}}{x} + \frac{4 x}{x} - \frac{3}{x}

Cancel

\frac{3 x ^{2}}{x} : 3 x

= 3 x + \frac{4 x}{x} - \frac{3}{x}

Cancel

\frac{4 x}{x} : 4

= 3 x + 4 - \frac{3}{x}

(1, 1, 1) X (- 1, - 10, 1)

\frac{4 + h - 2}{h}

- π (x - π)

\frac{( s + 1 )}{s \cdot ( s ^{2} + 1 )}

ln (2 x - 2 a) (x - a)^{3}

What is expand ((3x^2+4x-3))/x ?
The solution to expand ((3x^2+4x-3))/x is 3x+4-3/x