What is expand ln(2x-2a)(x-a)^3 ?

The solution to expand ln(2x-2a)(x-a)^3 is x^3ln(2x-2a)-3ax^2ln(2x-2a)+3a^2xln(2x-2a)-a^3ln(2x-2a)

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expand ln(2x-2a)(x-a)^3

expand

ln (2 x - 2 a) (x - a)^{3}

x^{3} ln (2 x - 2 a) - 3 a x^{2} ln (2 x - 2 a) + 3 a^{2} x ln (2 x - 2 a) - a^{3} ln (2 x - 2 a)

Solution steps

ln (2 x - 2 a) (x - a)^{3}

(x - a)^{3} = x^{3} - 3 a x^{2} + 3 a^{2} x - a^{3}

= ln (2 x - 2 a) (x^{3} - 3 a x^{2} + 3 a^{2} x - a^{3})

= ln (2 x - 2 a) (x^{3} - 3 a x^{2} + 3 a^{2} x - a^{3})

Distribute parentheses

= ln (2 x - 2 a) x^{3} + ln (2 x - 2 a) (- 3 x^{2} a) + ln (2 x - 2 a) \cdot 3 x a^{2} + ln (2 x - 2 a) (- a^{3})

Apply minus-plus rules

+ (- a) = - a

= x^{3} ln (2 x - 2 a) - 3 a x^{2} ln (2 x - 2 a) + 3 a^{2} x ln (2 x - 2 a) - a^{3} ln (2 x - 2 a)

e^{6 t} (t + e^{- 3 t})

\frac{( x - 2 ) ( x + 2 )}{x ^{4} ( 2 x + 7 )}

(2 x e^{- 2 x} + e^{- 2 x}) e^{2 x}

- \frac{2 x}{( x + y ) ^{3}}

(\frac{x + y - 4 β}{4}) (0, - 6, - 6)

What is expand ln(2x-2a)(x-a)^3 ?
The solution to expand ln(2x-2a)(x-a)^3 is x^3ln(2x-2a)-3ax^2ln(2x-2a)+3a^2xln(2x-2a)-a^3ln(2x-2a)