What are the solutions to the equation 4x^2+10=11x ?

The solutions to the equation 4x^2+10=11x are x= 11/8+i(sqrt(39))/8 ,x= 11/8-i(sqrt(39))/8

Find the zeros of 4x^2+10=11x

The zeros of 4x^2+10=11x are x= 11/8+i(sqrt(39))/8 ,x= 11/8-i(sqrt(39))/8

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4 x^{2} + 10 = 11 x

x = \frac{11}{8} + i \frac{39}{8}, x = \frac{11}{8} - i \frac{39}{8}

Solution steps

4 x^{2} + 10 = 11 x

Move

11 x

to the left side

4 x^{2} + 10 - 11 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 11 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 4 \cdot 10}{2 \cdot 4}

Simplify

(- 11)^{2} - 4 \cdot 4 \cdot 10 : 39 i

x_{1, 2} = \frac{- ( - 11 ) \pm 39 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 39 i}{2 \cdot 4}, x_{2} = \frac{- ( - 11 ) - 39 i}{2 \cdot 4}

x = \frac{- ( - 11 ) + 39 i}{2 \cdot 4} : \frac{11}{8} + i \frac{39}{8}

x = \frac{- ( - 11 ) - 39 i}{2 \cdot 4} : \frac{11}{8} - i \frac{39}{8}

The solutions to the quadratic equation are:

x = \frac{11}{8} + i \frac{39}{8}, x = \frac{11}{8} - i \frac{39}{8}

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What are the solutions to the equation 4x^2+10=11x ?
The solutions to the equation 4x^2+10=11x are x= 11/8+i(sqrt(39))/8 ,x= 11/8-i(sqrt(39))/8
Find the zeros of 4x^2+10=11x
The zeros of 4x^2+10=11x are x= 11/8+i(sqrt(39))/8 ,x= 11/8-i(sqrt(39))/8